C program to check if a given alphabet is vowel or consonant

In this article, we'll explore how to create a simple C program to determine whether a given alphabet is a vowel or a consonant.

Understanding Vowels and Consonants

In the English alphabet, there are five vowels: 'a', 'e', 'i', 'o', and 'u'. All other alphabets are considered consonants.

C program to check if a given alphabet is vowel or consonant

Let's delve into the C programming language to create a program that checks whether a user-input alphabet is a vowel or a consonant.

#include <stdio.h>

int main() {
    char ch;

    // Input from the user
    printf("Enter an alphabet: ");
    scanf(" %c", &ch);

    // Checking if the character is a vowel or a consonant
    if (ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u' ||
        ch == 'A' || ch == 'E' || ch == 'I' || ch == 'O' || ch == 'U') {
        printf("%c is a vowel.\\n", ch);
    } else if ((ch >= 'a' && ch <= 'z') || (ch >= 'A' && ch <= 'Z')) {
        printf("%c is a consonant.\\n", ch);
    } else {
        printf("%c is not a valid alphabet.\\n", ch);
    }

    return 0;
}

Output

Enter an alphabet: a
a is a vowel.

Vowel or Consonant Check: The program checks if the entered character matches any of the vowels. If so, it's identified as a vowel. Otherwise, it checks if the character is an alphabet and not a vowel, indicating it's a consonant. Invalid input (non-alphabetic characters) are handled as well.

In this article, we've created a simple C program that efficiently determines whether a given alphabet is a vowel or a consonant. Understanding the English alphabet's vowel and consonant structure and using conditional checks in C enables us to perform accurate classifications.